I'm building my packs with 0.15mm thick pure nickel strips that have no pattern (one piece of about 27mm wide nickel) so instead of having the typical 8mm wide serial connection, I have an area that is as wide as the cell (18mm).

So 18*0.15=2.7 which I devide that 2.7 by 4 in order to get the square area of the conductor in copper language which is 0.67mm that is about 19AWG copper wire per cell.

The strongest cell I use is 25R which I draw a max of 10A (half of the rated discharge rate).

So 10A through 19AWG.

I calculated that the length of the conductor between each two cells is about 10mm and if I multiply it for a 20S pack then I have 19 pieces of 10mm which is 19cm of total 19AWG length.

Can it be calculated like this?

If so, how do I calculate the resistance and voltage drop of 10A across a 19cm long 19AWG (0.65mm2) copper wire?

## Will Copper Serial Connection Add Something?

### Re: Will Copper Serial Connection Add Something?

R=Rho * L / A

rho of copper = 1.72 x 10^-8 at room temperature

L = 0.19 meter

A = 0.65 x 10^-6 meter^2

R = ( 1.72 * 10^-2 * 0.19 ) / 0.65 (i crossed off the 10^-6 on both sides of the divider)

R = 0.005 Ohm

R = 5 miliohm

voltage drop = I x R = 10 x 0.005 = 0.05V = 50mV

heat generated = Vdrop x I = 0.05 x 10 = 0.5W

rho of copper = 1.72 x 10^-8 at room temperature

L = 0.19 meter

A = 0.65 x 10^-6 meter^2

R = ( 1.72 * 10^-2 * 0.19 ) / 0.65 (i crossed off the 10^-6 on both sides of the divider)

R = 0.005 Ohm

R = 5 miliohm

voltage drop = I x R = 10 x 0.005 = 0.05V = 50mV

heat generated = Vdrop x I = 0.05 x 10 = 0.5W

### Re: Will Copper Serial Connection Add Something?

Thank you!nieles wrote: ↑Feb 11 2020 5:02amR=Rho * L / A

rho of copper = 1.72 x 10^-8 at room temperature

L = 0.19 meter

A = 0.65 x 10^-6 meter^2

R = ( 1.72 * 10^-2 * 0.19 ) / 0.65 (i crossed off the 10^-6 on both sides of the divider)

R = 0.005 Ohm

R = 5 miliohm

voltage drop = I x R = 10 x 0.005 = 0.05V = 50mV

heat generated = Vdrop x I = 0.05 x 10 = 0.5W

So there is no point in making an effort to go full copper for the serials since the loss is only 0.5W, am I right?